x*(ln(abs(x)))^(2/3)

Simple and best practice solution for x*(ln(abs(x)))^(2/3) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for x*(ln(abs(x)))^(2/3) equation:


D( x )

abs(x) <= 0

abs(x) <= 0

abs(x) <= 0

abs(x) <= 0

x in (-oo:+oo)

abs(x)

x in <0:+oo)

x <= 0

x in (-oo:0)

-x <= 0

abs(x) <= 0

/ | -x <= 0 i x in (-oo:0) | x <= 0 i x in <0:+oo)

x in (-oo:0)

0-x <= 0

-x <= 0 // * -1

x >= 0

(-oo:0)

x in <0:+oo)

x+0 <= 0 // - 0

x <= 0

x in (-oo:0) U (0:+oo)

x*(ln(abs(x)))^(2/3) = 0

x*(ln(abs(x)))^(2/3) = 0

x in (-oo:+oo)

abs(x)

x in <0:+oo)

x*(ln(x))^(2/3) = 0

x in (-oo:0)

x*(ln(-x))^(2/3) = 0

x*(ln(abs(x)))^(2/3) = 0

/ | x*(ln(-x))^(2/3) = 0 i x in (-oo:0) | x*(ln(x))^(2/3) = 0 i x in <0:+oo)

x in (-oo:0)

x*(ln(-x))^(2/3) = 0

x = 0

(ln(abs(x)))^(2/3) = 0

(ln(abs(x)))^(2/3) = 0

x in (-oo:+oo)

abs(x)

x in <0:+oo)

(ln(x))^(2/3) = 0

x in (-oo:0)

(ln(-x))^(2/3) = 0

(ln(abs(x)))^(2/3) = 0

/ | (ln(-x))^(2/3) = 0 i x in (-oo:0) | (ln(x))^(2/3) = 0 i x in <0:+oo)

x in (-oo:0)

(ln(-x))^(2/3) = 0

t_2 = ln(-x)

1*t_2^(2/3) = 0 // : 1

t_2^(2/3) = 0

t_2 = 0

ln(-x) = 0

ln(-x) = ln(e^0)

-x = e^0

x = -e^0

x in <0:+oo)

(ln(x))^(2/3) = 0

t_3 = ln(x)

1*t_3^(2/3) = 0 // : 1

t_3^(2/3) = 0

t_3 = 0

ln(x) = 0

ln(x) = ln(e^0)

x = e^0

x = 1

x*(ln(abs(x)))^(2/3) = 0 <=> x = 0 or x*(ln(abs(x)))^(2/3) = 0 <=> (ln(abs(x)))^(2/3) = 0

x in <0:+oo)

x*(ln(x))^(2/3) = 0

x = 0

(ln(abs(x)))^(2/3) = 0

(ln(abs(x)))^(2/3) = 0

x in (-oo:+oo)

abs(x)

x in <0:+oo)

(ln(x))^(2/3) = 0

x in (-oo:0)

(ln(-x))^(2/3) = 0

(ln(abs(x)))^(2/3) = 0

/ | (ln(-x))^(2/3) = 0 i x in (-oo:0) | (ln(x))^(2/3) = 0 i x in <0:+oo)

x in (-oo:0)

(ln(-x))^(2/3) = 0

t_5 = ln(-x)

1*t_5^(2/3) = 0 // : 1

t_5^(2/3) = 0

t_5 = 0

ln(-x) = 0

ln(-x) = ln(e^0)

-x = e^0

x = -e^0

x in <0:+oo)

(ln(x))^(2/3) = 0

t_6 = ln(x)

1*t_6^(2/3) = 0 // : 1

t_6^(2/3) = 0

t_6 = 0

ln(x) = 0

ln(x) = ln(e^0)

x = e^0

x = 1

x*(ln(abs(x)))^(2/3) = 0 <=> x = 0 or x*(ln(abs(x)))^(2/3) = 0 <=> (ln(abs(x)))^(2/3) = 0

x in { 0}

x = 1

See similar equations:

| 2y^3*y+3z^2= | | (7w-9x)(7w+9x)= | | 6m+18m+5= | | 2y^3+3z^2*y= | | x+3y+x+2y+5x= | | 4x^2-7x-225=0 | | 2y^3*3z^2+y= | | 2(t+1)+5=3 | | 2y^3*3z^2*y= | | -8(2t+3)=-104 | | -8(s+3)=44 | | -(c+4)=4 | | 3(4s+6)=186 | | s=(4/3)3.14r^3 | | 1/3x-2/5y=10 | | 1/2x-2/5y=10 | | 8(2l+1)=81 | | y=1/2x^-15 | | x+3=4y+1 | | x^2-a(x+1)-b=0 | | X+125-x=250 | | 0x=125 | | 2cos^2(2x)+3cos^2x=2 | | y+y=576 | | 5x^2-4ax-a^2=0 | | h(x)=ln(x^3+4) | | 2x^4-3x^2-16x+24=0 | | cos(45)=3.9/x | | Y=(5x-1)*(4+3x) | | 5x-6y=4whatsx | | 8(2m-3)=-2(m-42) | | 6(-y+2)=2p+5 |

Equations solver categories